Решите в тетраде!!!!!!!

A)
4 - m = 4 - log₅4 = log₅625 - log₅4 = log₅ 625/4
log₅125 < log₅ 625/4 < log₅ 625
3 < log₅ 625/4 < 4
4 - m ∈ [3; 4]

б)
$-\frac{2}{m}=-\frac{2}{log_54}=-\frac{log_525}{log_54}=-log_425$
-log₄64 < -log₄25 < -log₄16
-3 < -log₄25 < -2
-2/m ∈ [-3; -2]

в)
$\sqrt{m+1}=\sqrt{log_54+1}=\sqrt{log_54+log_55}=\sqrt{log_520} \\\sqrt{log_55} \ \textless \ \sqrt{log_520}\ \textless \ \sqrt{log_525} \\1 \ \textless \ \sqrt{log_520}\ \textless \ \sqrt2$
√(m + 1) ∈ [1; 2]

г)
$m^2=log^2_54 \\ log^2_51\ \textless \ log^2_54\ \textless \ log^2_55 \\0\ \textless \ log^2_54\ \textless \ 1$
m² ∈ [0; 1]