1,1x+1=x-2. 1,2*(x-5)=0,2x+6. 0,5*(x-2)=3x+4*(x-0,5).

Question

1,1x+1=x-2. 1,2*(x-5)=0,2x+6. 0,5*(x-2)=3x+4*(x-0,5).

Comments

1,1x+1=x-2

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varog ajutatina

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multumesc

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problema

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demonstrati ca suma a trei numere naturale consecutive este un multiplu al lui 3

Answer 1

1.1x +1=x-2
1.1x - x = -2-1
0.1x= -3
x=-3 ÷ 0.1= -30 ÷1
x=-30
1.1*(-30) +1 = -30-2
-33 +1=-32
-32=-32

1.2(x-5) =0.2x+6
1.2x -6= 0.2x+6
1.2x- 0.2x = 6+6
x= 12
1.2(12-5) = 0.2*12+6
1.2* 7= 2.4+6
8.4=8.4

0.5(x-2)=3x+4(x-0.5)
0.5x -1 = 3x +4x -2
0.5x-1 = 7x -2
0.5x-7x=-2+1
-6.5x= -1
x= (-1) ÷  (-6.5) = 10/65 = 2/13
x=2/13
0.5 (2/13  -2 ) = 3*   2/13 + 4* (2/13  -0.5)
5/10   *   (-  1  11/13)  =  6/13   +   4* (4/26  -  13/26) 
1/2   *   (-24/13 )   =  6/13   +  4/1 *   (- 9/26)
-12/13   =   6/13  -    (2*9)/ (1*13)
-12/13  = 6/13   - 18/13
- 12/13= -12/13