Помогите с алгеброй!!! 1.)(x-2)(1-x)=x(4-x) 2).9x+5/3x+10-3x+7/x+6=0 3)(x-2)(x-3)>0...

1) (x-2)(1-x) = x(4-x)
x - x² - 2 + 2x = 4x - x²
x + 2x - 4x - x² + x² = 2
-x = 2
x = -2
Ответ: x = -2
2) $\frac{9x+5}{3x+10} - \frac{3x+7}{x+6} = 0$
9x² + 59x - (9x² + 51x + 70) = -30
8x - 70 = -30
8x = 40
x = 5
Ответ: x = 5
3) (x-2)(x-3) > 0
$\left \{ {{ \left \{ {{x-2\ \textless \ 0} \atop {x-3\ \textless \ 0}} \right.} \atop { \left \{ {{x-2\ \textgreater \ 0} \atop {x-3\ \textgreater \ 0}} \right.}} \right. \left \{ {{x\ \textless \ 2} \atop {x\ \textgreater \ 3}} \right.$
Ответ: x ∈ (-∞,2) ∪ (3,∞)
4) $\left \{ {{x\ \textgreater \ 4} \atop {x\ \textless \ 6}} \right.$