1) y = 0
4x^2 = 7
x^2 = 7/4
x = +- √7 / 2
2) y ≠ 0
2x - y = 1
y = 2x - 1
4x^2 + (2x - 1)^2 -2x(2x-1) = 7
4x^2 + 4x^2 - 4x + 1 - 4x^2 + 2x = 7
4x^2 - 2x + 1 = 7
4x^2 - 2x - 6 = 0
2x^2 - x - 3 = 0
x = -1 x = 3/2
y = -3 y = 2
Ответ: (√7/2; 0), (-√7/2; 0), (-1; -3), (3/2; 2)