2sin^3x-3tg4x-4 Найдите производную
(2sin3x-3tg4x-4)' = (2sin3x)' - (3tg4x)' - (4)' = 2(sin3x)' - 3(tg4x)' = 2 cos 3x * (3x)' - 3*[1/cos^2(4x) ] * (4x)' = 6 cos 3x - 12/ cos^2(4x)