Решите систему уравнения

Решите задачу:

$\left \{ {{3^{x}\cdot 2^{y}=\frac{1}{9}} \atop {y-x=2}} \right. \; \left \{ {{9\cdot 3^{x}\cdot 2^{x+2}=1} \atop {y=x+2}} \right. \; \left \{ {{3^2\cdot 3^{x}\cdot 2^{x+2}=1} \atop {y=x+2}} \right. \; \left \{ {{3^{x+2}\cdot 2^{x+2}=1} \atop {y=x+2}} \right. \\\\ \left \{ {{(3\cdot 2)^{x+2}=1} \atop {y=x+2}} \right. \; \left \{ {{6^{x+2}=6^0} \atop {y=x+2}} \right. \; \left \{ {{x+2=0} \atop {y=x+2}} \right. \; \left \{ {{x=-2} \atop {y=0}} \right. \\\\Otvet:\; \; (-2,0).$