!!!рЕшИтЕ НЕРАвЕнСТВо!!!! √x^2-2x < x+5
ОДЗ: x^2 - 2x >= 0 x(x - 2) >= 0 x ∈(-∞; 0] ∪ [2; ∞) x + 5 >= 0 x >= -5 x ∈[-5; 0] ∪ [2; ∞) x^2 - 2x < x^2 + 10x + 25 12x + 25 > 0 12x > -25 x > - 25 / 12 С учетом ОДЗ x ∈ (-25/12; 0] ∪ [2; ∞)