(b²-3)³-(b²-3)*(b⁴+3b²+9)

Question

(b²-3)³-(b²-3)*(b⁴+3b²+9)

Answer 1

(b²-3)³-(b²-3)(b⁴+3b²+9)=
=(b²-3)((b²-3)²-(b⁴+3b²+9))=
=(b²-3)(b⁴-6b²+9-b⁴-3b²-9)=
=(b²-3)(-9b²)=
= -9b⁴+27b²