Log5 (4-x)+log5 ( x+3)=log5 10
Log5 (4-x) + log5 (x+3) = log5 10 , x∈(-3,4) log5 (4-x)(x+3)= log5 10 (4-x)(x+3)=10 4x+12-x²-3x=10 -x²+x+12-10=0 -x²+x+2=0 x²-x-2=0 (x-2)(x+1)=0 (a.b=0⇔a=0 ∨ b=0) a)x-2=0, x=2 , 2∈(-3,4) b)x+1=0,x=-1, -1∈(-3,4) Otvet: x=2, x=-1