Помогите sin^2 x+3sinx=2

Question

Помогите
sin^2 x+3sinx=2

Answer 1

Sinx=t
t^2+3t=2
t^2+3t-2=0
Д=(-3)^2-4*1*(-2)=9+16=25
t1,2=-3+-5/2
t1=1
t2=-4

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