Log4(x+1)-2=log4 (3-x)
{x+1>0⇒x>-1 {3-x>0⇒x<3<br>x∈(1;3) log(4)(x+1)=log(4)[(3-x)*16] x+1=48-16x x+16x=48-1 17x=47 x=2 13/17