4sin^2 x+6sin x=-4cos^2x

Question

4sin^2 x+6sin x=-4cos^2x

Answer 1

4sin²x+4cos²x+6sinx=0
4(sin²x+cos²x)+6sinx=0
sinx=-2/3
x=(-1)^(n+1)*arcsin2/3+πn, n€Z