Sin(-45градусов)tgП/3+cos(-45)ctgП/6

Решите задачу:

$sin( -\frac{\pi}{4} )*tg( \frac{\pi}{3} )+cos(- \frac{\pi}{4} )*ctg( \frac{\pi}{6} )=$
$=-sin(\frac{\pi}{4} )*tg( \frac{\pi}{3} )+cos(\frac{\pi}{4} )*ctg( \frac{\pi}{6} )=$
$=- \frac{ \sqrt{2} }{2}* \frac{sin( \frac{\pi}{3} )}{cos( \frac{\pi}{3} )} + \frac{ \sqrt{2} }{2} * \frac{cos( \frac{\pi}{6} )}{sin( \frac{\pi}{6} )} =$
$=- \frac{ \sqrt{2} }{2}* \frac{ \frac{ \sqrt{3} }{2}}{ \frac{1}{2}} + \frac{ \sqrt{2} }{2} * \frac{\frac{ \sqrt{3} }{2}}{ \frac{1}{2}} =0$