(х-1)(х^2+4x+4)=4(x+2)

Question

(х-1)(х^2+4x+4)=4(x+2)

Answer 1

(x -1)(x +2)² =4(x +2)

(x -1)(x +2)² -4(x +2)

(x +2)((x-1)(x+2) -4) =0

(x +2)(x²+2x-x-2-4) =0

(x +2)(x² +x -6) =0

x +2 =0, x1 = -2

x² +x -6 =0
D=b² -4ac(a=1,b=1,c= -6)

D =1 -4*6 =25 =5²

x2,x3 =(-b+-vD)/2a

x2 =(-1 -5)/2 = -3

x3 =(-1 +5)/2 =2

ответ: x= -3, x= -2, x =2