Помогите.Не могу решить!Дам 17 баллов! 5 4/19*3 4/7+1 15/19:7/25-1 2/3

Решите задачу:

$5 \frac{4}{19} * 3 \frac{4}{7} + 1 \frac{15}{19} : \frac{7}{25} - 1 \frac{2}{3} =10 \frac{220}{399} \\ \\ 1) 5 \frac{4}{19} * 3 \frac{4}{7} = \frac{5*19+4}{19} * \frac{3*7+4}{7} = \frac{99*25}{19*7} = \frac{2475}{133} =18 \frac{81}{133} \\ \\ 2) 1 \frac{15}{19} : \frac{7}{25}= \frac{1*15+19}{19} * \frac{25}{7} = \frac{34*25}{19*7} = \frac{850}{133} = 6 \frac{52}{133} \\ \\ 3) 18 \frac{81}{133}-6 \frac{52}{133} = (18-6) + \frac{81-52}{133} = 12 \frac{29}{133} \\ \\$
$4) 12 \frac{29}{133} - 1 \frac{2}{3} = 12 \frac{87}{399} - 1 \frac{266}{399} = 10 \frac{220}{399}$