Решите уравнения с фотографии

1) $\frac{(x-6)(x-6)-(x-12)(x-12)}{(X-12)(x-6)} = \frac{ x^{2} -6x-6x+36-( x^{2} -12x-12x+144)}{ x^{2} -6x-12x+72} =$
$= \frac{ x^{2} -12x+36- x^{2} +24x-144}{ x^{2} -18x+72} = \frac{12x-108}{ x^{2} -18x+72}$
$\frac{12x-108}{ x^{2} -18x+72} = \frac{5}{6}$
6(12х-108)=5(х²-18х+72)
72х-648=5х²-90х+360
5х²-162х+1008=0

D=b²-4ac=(-162)²-4·5·1008=26244-20160=6084

$x_{1} = \frac{162- \sqrt{6084}}{2*5} = \frac{162-78}{10} = \frac{84}{10} =8,4$
$x_{2} = \frac{162+ \sqrt{6084}}{2*5} = \frac{162+78}{10} = \frac{240}{10} =24$