Log7(x^2+6x)=1 плиззз

Question

Log7(x^2+6x)=1 плиззз

Answer 1

Log₇(x²+6x)=1
 7¹=x²+6x
x²+6x-7=0
D=36+28=64
x=(-6+8)/2=1
x=(-6-8)/2=-7

Answer 2

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