Log1/2(2x-5)>-1 помогите пожалуйста

$log_{\frac{1}{2}}(2x-5)\ \textgreater \ -1\ \textless \ =\ \textgreater \ log_{\frac{1}{2}}(2x-5)\ \textgreater \ log_{\frac{1}{2}}2$

ОДЗ:
$2x-5\ \textgreater \ 0\\2x-5\ \textless \ 2$

$2\ \textgreater \ 2x-5\ \textgreater \ 0\\7\ \textgreater \ 2x\ \textgreater \ 5\\3,5\ \textgreater \ x\ \textgreater \ 2,5$
\\\\α//////β//////////c///
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где $\alpha=0$ , $\beta=2,5$ , $c=3,5$ .
x∈(2,5; 3,5)