Решите неравенство log5(3x+4)≤2

Log₅(5x+4)≤2. 2=log₅5²=log₅25
основание логарифма а=5, 5>1. знак неравенства не меняем
$\left \{ {{3x+4\ \textgreater \ 0} \atop {3x+4 \leq 25}} \right. , \left \{ {{3x\ \textgreater \ -4} \atop {3x \leq 21}} \right. , \left \{ {{x\ \textgreater \ - \frac{4}{3} } \atop {x \leq 7}} \right.$

x∈(-4/3;7]