Вычисление интегралов

Решите задачу:

$\int _0^13e^{x}\, dx=3e^{x}|_0^1=3(e-1)\\\\\int _0^3\frac{x^2}{6}dx=\frac{1}{6}\cdot \frac{x^3}{3}|_0^3=\frac{1}{18}\cdot 3^3=\frac{3}{2}\\\\\int _{-2}^0(1+0,5x)dx=\frac{1}{0,5}\cdot \frac{(1+0,5x)^2}{2}|_{-2}^0=1-0=1\\\\\int _\frac{\pi}{3}}^{\pi }sin(\frac{x}{2}-\frac{\pi}{6})dx=-2\cdot cos(\frac{x}{2}-\frac{\pi}{6})|_{\frac{\pi}{3}}^{\pi }=\\\\=-2\cdot (cos\frac{\pi}{2}-cos0)=-2(0-1)=2$