x=√32 y=

Решите задачу:

$\frac{1}{x}- \frac{x+6y}{6xy} = \frac{1*6y}{x*6y}- \frac{x+6y}{6xy} = \frac{6y}{6xy}- \frac{x+6y}{6xy} = \frac{6y-(x+6y)}{6xy}= \frac{6y-x-6y}{6xy}=$
$= \frac{-x+6y-6y}{6xy}= \frac{-x}{6xy}=- \frac{1*x}{6*x*y} =- \frac{1}{6*y} =- \frac{1}{6y} =-1:(6y)=$
$=-1:(6* \frac{1}{9} )=-1: \frac{6*1}{9} =-1: \frac{2*3}{3*3}=-1: \frac{2}{3}=-1* \frac{3}{2}=-1*1.5=$
$=-1.5=- \frac{3}{2}$