Помогите пожалуйста найдите 8 sin a если tg a = 0,75 и -П < a < -П/2

Решите задачу:

$8\sin \alpha\ -\ ?,\ \ -\pi\ \textless \ \alpha\ \textless \ -\frac{\pi}{2},\\tg \alpha =0,75.\\\\1+ctg^2 \alpha =\frac{1}{\sin^2 \alpha },\\\\\sin^2 \alpha =\frac{1}{1+ctg^2 \alpha },\\\\\sin^2 \alpha =\frac{1}{1+\frac{1}{tg^2 \alpha }},\\\\\sin \alpha =\pm\sqrt{\frac{1}{1+\frac{1}{tg^2 \alpha }}},\\\\-\pi\ \textless \ \alpha\ \textless \ -\frac{\pi}{2}\ \to \ \sin \alpha =-\sqrt{\frac{1}{1+\frac{1}{tg^2 \alpha }}},\\\\\sin \alpha =-\sqrt{\frac{1}{1+\frac{1}{0,75^2}}}=-\sqrt{0,36}=-\sqrt{0,6^2}=-0,6;\\\\8\sin \alpha =8\cdot (-0,6)=-4,8.\\\\OTBET:\ 8\sin \alpha=-4,8$