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Решите задачу:

$\frac{3^{-1}-(\frac{2}{3})^{-2}}{2-(\frac{3}{4})^2} \cdot (5^0-\frac{1}{6})^{-1}+2\cdot (10)^{-1}=\\\\= \frac{\frac{1}{3}-\frac{9}{4}}{2-\frac{9}{16}} \cdot (1-\frac{1}{6})^{-1}+\frac{2}{10}=\\\\= \frac{\frac{4-27}{12}}{\frac{32-9}{16}} \cdot (\frac{5}{6})^{-1}+\frac{1}{5}= \frac{-23\, \cdot \; 16}{12\, \cdot \; 23} \cdot \frac{6}{5}+\frac{1}{5}= -\frac{16}{12} \cdot \frac{6}{5}+\frac{1}{5}=\\\\= -\frac{16}{2\cdot 5} +\frac{1}{5}= \frac{-16+2}{10} =\frac{-14}{10}=-1,4$