{3x+y=3
{log(3)(5x+4y)=log(3)(y+5)
y=3-3x
5x+4(3-3x)=3-3x+5
5x+12-12x=8-3x
4x=4 => x=1
y=3-3=0
ОДЗ: y+5>0 y>-5; 12-7x>0 7x<12 x<12/7</p>
Ответ: (1;0)