X²-16 ≥ 0 x²+10x < 0

Question

X²-16 ≥ 0 x²+10x < 0

Answer 1

X²-16 ≥ 0
(x-4)(x+4)≥0
x∈(-∞; -4]∨[4;+∞)

x²+10x < 0
x(x+10)<0<br>x∈(-10; 0)