Задание 8................

Question

Задание 8................

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Answer 1

Дано
W(С)=81.82%=0.8182
W(H)=18.18%=0.1818
V(CxHy)=1 L
m(CxHy)=2.6 g
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CxHy-?
M(CxHy)=m(CxHy)*Vm/V(CxHy)=2.6*22.4/1=58.24g/mol
CxHy/58.24 = 0.8182/12 : 0.1818/1
CxHy=4:10
C4H10
ответ бутан