Помогите сделать химию )
1) 1.4 Xg KOH+HNO3-->KNO3+H2O 56 101 M(KOH)=56g/mol M(KNO3)=101 g/mol 1.4/56 = X/101 X=2.525g 2) 14 Xg BaO+H2SO4-->BaSO4+H2O 153 233 M(BaO)=153 g/mol M(BaSO4)=233 g/mol 14/153 = X/233 X=21.32 g