1)x<0<br>1+2/x-23/x²≤0
(x²+2x-23)/x²≤0
x²+2x-23=0
D=4+92=96
x1=(-2-4√6)/2=-1-2√6
x2=-1+2√6
+ _ _ +
-------------[-1-2√6]------------(0)--------[-1+2√6]--------------
x∈[-1-2√6;0)
2)x>0
1-2/x-23/x²≤0
(x²-2x-23)/x²≤0
x²-2x-23=0
D=4+92=96
x1=(2-4√6)/2=1-2√6
x2=1+2√6
+ _ _ +
-------------[1-2√6]------------(0)--------[1+2√6]--------------
x∈(0;1+2√6]
Ответ x∈[-1-2√6;0) U (0;1+2√6]