1.4.
a≠0,b≠0
1)a²/4b³+2/a=(a³+8b³)/4ab³
2)a/2b³-1/b+2/a=(a²-2ab+4b²)/2ab²
3
[(a-2b)²+8ab):(4+2a/b)=(a²-4ab+4b²+8ab):(4b+2a)/b=(a+2b)²*b/[2(2b+a)]=
=(a+2b)*b/2
4)
(a+2b(a²-2ab+4b²)/4ab³ *2ab²/(a²-2ab+4b²)*2/[(a+2b)*b]=1/b²
1.5
1)(3/2*a²-2ab+2/3*b²):(1/4*a²-1/9*b²)=(9a²-12ab+4b²)/6:(9a²-4b²)/36=
(3a-2b)²/6*36/[(3a-2b)(3a+2b)]=6(3a-2b)/(3a+2b)
2)6b:(3/4*a+1/2*b)=6b:(3a+2b)/4=6b*4/(3a+2b)=24b/(3a+2b)
3)6(3a-2b)/(3a+2b)+24b/(3a+2b)=(18a-12b+24b)/(3a+2b)=
=(18a+12b)/(3a+2b)=6(3a+2b)/(3a+2b)=6