Помогите решить пример
1/ ((x-y)(x-z)) - 1/ ((z-х)(у-х)) = = 1/ ((х-у)(x-z) ) - 1/ ( -(x-z) * -(x-y)) = = 1/ ((x-y)(x-z)) - 1/ ((x-y)(x-z))=0
1/[(x-y)(x-z)]-1/[-(x-z)*(-(x-y))]=1/[(x-y)(x-z)]-1/[(x-y)(x-z)]=0