Упростите
A^0,5=√a 1)3/[√a(√a-3)]-a√a/[a(√a-3)(√a+3)]=(3a+9√a-a√a)/[a(√a-3)(√a+3)]= =√a(3√a+9-a)/[a(√a-3)(√a+3)]=(3√a+9-a)/[√a(√a-3)(√a+3)] 2)[a(√a-3)(√a+3)]:(3√a+9-a)/(√a+3)=[a(√a-3)(√a+3)]*(√a+3)/(3√a+9-a)= =1/[√a(√a-3)]=1/(a-3√a)