Помогите!!!!!!!!!лвллу

Решите задачу:

$log_2(x^2-7x+6) \leq 1+log_27\; ,\; \; \; ODZ:\; x^2-7x+6\ \textgreater \ 0\\\\(x-1)(x-6)\ \textgreater \ 0\; ,\qquad +++(1)---(7)+++\\\\x\in (-\infty ,1)\cup (6,+\infty )\; ,\\\\log_2(x^2-7x+6) \leq log_22+log_27\\\\log_2(x^2-7x+6) \leq log_214\\\\x^2-7x+6 \leq 14\\\\x^2-7x-8 \leq 0\; \\\\(x+1)(x-8) \leq 0\quad +++[-1\, ]---[\, 8\, ]+++\\\\x\in [\, -1,8\, ]\\\\ \left \{ {{x\in (-\infty ,1)\cup (6,+\infty )} \atop {x\in [-1,8\, ]}} \right. \; \Rightarrow \; \; x\in [-1,1)\cup (6,8\, ]$