Помогите срочно! log 8 (x+10) - log 8 x = 1 log 5 (x+12) + log 5 (x-12) = 2 log 1//2...

Question

Помогите срочно!

log 8 (x+10) - log 8 x = 1

log 5 (x+12) + log 5 (x-12) = 2

log 1//2 (3x-1) = -4

Answer 1

1) log 8 (x+10)/x = log 8 8
x+10/x=8
x+10=8x
7x=10
x=10/7
2)log 5 (x+12)(x-12) = log 5 25
(x+12)(x-12)=25
x^2-144=25
x^2=169
x=+-13
3)log 1/2 (3x-1) = log 1/2 16
3x-1=16
3x=17
x=17/3