Помогите решить: 12xy-8y2 ------------- 4y 2) 9xy3-3y2 ------------- 3y2 3) xy-y...

1) $\frac{12xy-8y^2}{4y}=\frac{4y(3x-2y)}{4y}=3x-2y$
2) $\frac{9xy^3-3y^2}{3y^2}= \frac{3y^2(3xy-1)}{3y^2}=3xy-1$
3) $\frac{xy-y}{4y^2} = \frac{y(x-1)}{4y^2}= \frac{x-1}{4y}$
4) $\frac{3xy-y}{5y^2-y} = \frac{y(3x-1)}{y(5y-1)}=\frac{3x-1}{5y-1}$
5) $\frac{2xy^2-8y}{2xy-4x}=\frac{2y(xy-4)}{2x(y-2)}=\frac{y(xy-4)}{x(y-2)}$