РЕШИТЕ ПОЖАЛУЙСТА........................

Решите задачу:

$1. \int\limits { x^{2} +6x+1} \, dx = \frac{ x^{3} }{3}+ \frac{ 6x^{2} }{2} + x +const = \frac{ x^{3} }{3}+3 x^{2} +x+const \int\limits {8x- x^{6} } \, dx = \frac{8 x^{2} }{2}- \frac{ x^{7} }{7}+const = 4 x^{2} - \frac{ x^{7} }{7}+const$

$2. \int\limits {5-2 x^{2} } \, dx = 5x- \frac{2 x^{3} }{3}+const$
$(-3;-8): 5(-3)-2 (-3)^{2}+const=-8 -15+18+const = -8 const = -11$
$F(x) = 5x- \frac{2 x^{3} }{3} - 11$

$3. \int\limits {2-9 x^{2} } \, dx = 2x-3 x^{3} + const$
$F(3) = 2*3 - 3*3^3 + const \ \textless \ 0 6-81+const \ \textless \ 0 const \ \textless \ 75$
$F(x) = 2x - 3 x^{3} + 74$

$4. \int\limits^{-1}_{-3} { x^{2} -4x+2} \, dx = (\frac{ x^{3} }{3}-2 x^{2} +2x) = ( \frac{-1}{3}-2-2 ) - ( -9 - 18 -6 )$
$= - \frac{1}{3} - 4 + 33 = 28 \frac{2}{3}$