Помогите с 11 пожалуйста

A) $\frac{13}{15}+ \frac{5}{11} + \frac{2}{15} + \frac{4}{11} =( \frac{13}{15}+ \frac{2}{15})+( \frac{5}{11} + \frac{4}{11})= \frac{15}{15}+ \frac{9}{11}=1+ \frac{9}{11}=1 \frac{9}{11}$
б) $(2 \frac{11}{30} + \frac{9}{14})+ (\frac{5}{14}+\frac{19}{30} )=2 \frac{11}{30} + \frac{9}{14}+ \frac{5}{14}+\frac{19}{30}= \\ =(2 \frac{11}{30} +\frac{19}{30})+(\frac{5}{14}+\frac{9}{14})=2 \frac{30}{30}+ \frac{14}{14}=3+1=4$
в) $( \frac{29}{22}+ \frac{1}{6})- \frac{7}{22}= \frac{29}{22}+ \frac{1}{6}- \frac{7}{22}=(\frac{29}{22}- \frac{7}{22})+ \frac{1}{6}= \frac{22}{22}+ \frac{1}{6}=1+\frac{1}{6}=1\frac{1}{6}$
г) $\frac{35}{34}-( \frac{1}{34}+ \frac{7}{18} )=\frac{35}{34}- \frac{1}{34}- \frac{7}{18}=\frac{34}{34}- \frac{7}{18}=1- \frac{7}{18}=\frac{18}{18}- \frac{7}{18}=\frac{11}{18}$