Log_3 (5-3x) + log_1\3 3≤0
Log-3(5 - 3x) + Log-1/3 3 <= 0<br>ОДЗ 5 - 3x > 0 3x < 5 x < 5/3 = 1 2/3 Log-3(5 - 3x) - 1 <= 0<br>Log-3(5 - 3x) <= 1<br>Log_3(5 - 3x) <= Log_3 3<br>5-3x <= 3<br>3x >= 5 - 3 3x >= 2 x >= 2/3 Ответ. [2/3; 1 2/3)