Найти область определения функции f(x)=

Решите задачу:

$f(x)=\sqrt{log_{0,3} \frac{2x-4}{8-x} }\\\\ODZ:\quad \left \{ {{log_{0,3} \frac{2x-4}{8-x} \geq 0 } \atop { \frac{2x-4}{8-x}\ \textgreater \ 0 }} \right. \; \left \{ {{ \frac{2x-4}{8-x} \leq 1} \atop { \frac{2(x-2)}{-(x-8)} \ \textgreater \ 0}} \right. \; \left \{ {{ \frac{2x-4}{8-x}-1 \leq 0 } \atop { \frac{x-2}{x-8} \ \textless \ 0}} \right. \; \left \{ {{ \frac{3x-12}{-(x-8)} \leq 0 } \atop {\frac{x-2}{x-8}\ \textless \ 0}} \right. \\\\a)\; \; \frac{3(x-4)}{-(x-8)} \leq 0\; ;\; \; \; ---[\, 4\, ]+++(8)---\\\\x\in (-\infty ,4\, ]\cup (8,+\infty )$

$b)\; \; \frac{x-2}{x-8} \ \textless \ 0\; ;\; \; +++(2)---(8)+++\\\\x\in (2,8)\\\\c)\; \; \left \{ {{x\in (-\infty ,4\, ]\cup (8,+\infty )} \atop {x\in (2,8)}} \right. \; \; \; \Rightarrow \; \; \; x\in \varnothing$