(x+2)/(x-1)=(x+4)/(x-3)
(x+2)*(x-3)=(x+4)*(x-1)
x²-3x+2x-6=x²-x+4x-4
x²-x-x²-3x=-4+6
-4x=2
x=2:(-4)=-1/2
x²+y²=2 x²+y²=2 y²+y²=2 2y²=2 y²=1 y=1 y=-1
x-y=0 x=y x=1 x=-1
((x-3)(x+2))/(x(x+1)²)≥0
x-3≥0 x≥3
x+2≥0 x≥-2
x(x+1)²≠0 x≠0
(x+1)²≠0 ⇒ x≠-1
- - +
-----------------------(-2)--------------------(3)---------------------
x∈[3;+∞)