D=4^{2}-4*3*1=16-12=4
\sqrt{D}=2
x_{1}=\frac{-4-2}{6}" alt="3x^{2}+4x+1\geq0
D=4^{2}-4*3*1=16-12=4
\sqrt{D}=2
x_{1}=\frac{-4-2}{6}" align="absmiddle" class="latex-formula">
x_{2}=\frac{-4+2}{6}
x_{2}=-\frac{1}{3}
(-\infty;-1]\cup[-\frac{1}{3};+\infty)" alt="x_{1}=-1
x_{2}=\frac{-4+2}{6}
x_{2}=-\frac{1}{3}
(-\infty;-1]\cup[-\frac{1}{3};+\infty)" align="absmiddle" class="latex-formula">