1) sin 13П/6 2) tg(-11П/6) 3)

Question

1) sin 13П/6 2) tg(-11П/6) 3)

Answer 1

sin(13π/6)= sin(2π+π/6)=sinπ/6=1/2

tg(-11π/6)=-tg(11π/6)=-tg(2π-π/6)=-tg(-π/6)=tgπ/6=√3/3