1)0,6(4x-12)-0,4(5x-7)при x=41/6

Question

1)0,6(4x-12)-0,4(5x-7)при x=41/6

Answer 1

0,6(4x-12)-0,4(5x-7)=2,4x-7,2-2x+2,8=0,4x-3,4=(41*4)/(6*10)-3,4=
=41/(3*5)-3,4=41/15-3,4=41/15-34/10=82/30-102/30=-20/30= -2/3

Answer 2

1) 0,6( 4х - 12 ) - 0,4( 5х - 7 ) = 2,4х - 7,2 - 2х + 2,8 = 0,4х - 4,4
2) х = 41/6
а) 0,4х - 4,4 = 0,4•( х - 11 )
б) 41/6 - 11 = 6 5/6 - 10 6/6 = - 4 1/6
в) 0,4 • ( - 4 1/6 ) = 2/5 • ( - 25/6 ) = - 5/3 = - 1 2/3
Ответ ( - 1 2/3 )