Решите систему неравенств:

$\left\{{{log_{0,1}(x^2-12)\ \textless \ log_{0,1}(-x)}\atop{2^{x-1}\ \textgreater \ \frac{1}{8}}}\right.\left\{{{x^2-12\ \textless \ log_{0,1}^{log_{0,1}(-x)}}\atop{2^{x-1}\ \textgreater \ 2^{-3}}}\right.\left\{{{x^2-12\ \textless \ -x}\atop{x-1\ \textgreater \ -3}\right.\left\{{{x^2+x-12\ \textless \ 0}\atop{x\ \textgreater \ -2}\right.\\D=\sqrt{1^2-4*1*(-12)}=\sqrt{1+48}=\sqrt{49}=7\\x_1=\frac{-1+7}{2}=3\\x_2=\frac{-1-7}{2}=-4$

x∈(–4; 3), но и x∈(–2; +∞) – решений системы нет.