Сократите дробь 1)2m^2-72n^2\(4m+24n)^2 2)a^2-8\ab-a-2b+2 3)a^3+2a^2b+ab^2\a^3-ab^2

Решите задачу:

$1)\frac{2m^2-72n^2}{(4m+24n)^2} = \frac{2(m^2-36n^2)}{(4(m+6n))^2}=\frac{2(m-6n)(m+6n)}{16(m+6n)^2}=\frac{(m-6n)}{8(m+6n)}$

$2) \frac{a^3-8}{ab-a-2b+2}=\frac{a^3-8}{a(b-1)-2(b-1)}=\frac{(a-2)(a+2a+4)}{(a-2)(b-1)}=\frac{(a+2a+4)}{(b-1)}$

$3) \frac{a^3+2a^2b+ab^2}{a^3-ab^2} =\frac{a(a^2+2ab+b^2)}{a(a^{2} -b^2)}= \frac{(a+b)^{2}}{(a -b)(a+b)}= \frac{a+b}{a-b}$