=(3^(1/2)*9^(1/6)^(1/2)/27^(1/4)=(3^(1/2)*3^(1/3))^(1/2)/27^(1/4)=
=(3^(5/6))^(1/2)/3^(3/4)=3^(5/12)/3^(3/4)=3^(5/12-3/4)=3^(-1/3)=1/∛3.
∛9=3^(2/3)
√((3^1/2)*3(2/3))=√(3^(1/2+2/3))=√(3^(5/6))=3^(5/6)^(1/2)=3^(5/12)
27^(1/4)=3^(3/4)
3^(5/12)/3^(3/4)=3^(5/12-3/4)=3^(-1/3)=1/∛3.