Срочно надо ( 4x ) / ( x + 3 ) > x + 1

Question

Срочно надо ( 4x ) / ( x + 3 ) > x + 1

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Answer 1

4x/(x+3)-(x+1)>0
(4x-x²-x-3x-3)/(x+3)>0
(x²+3)/(x+3)<0<br>x²+3>0 при любом х⇒x+3<0⇒x<-3<br>x∈(-∞;-3)