17(3c+5d)+6c-28d при c+d =2

Question

17(3c+5d)+6c-28d при c+d =2

Answer 1

17(3c + 5d) + 6c - 28d = 51c + 85d + 6c - 28d = 57c + 57d = 57(c + d)
c + d = 2
57 * 2 = 114