Iog2(x+3)-Iog2(4x-5)=0

Question

Iog2(x+3)-Iog2(4x-5)=0

Answer 1

Log(2) ( X + 3 ) - Log(2) ( 4x - 5 ) = 0
Log(2) ( X + 3 ) = Log(2) ( 4х - 5 )
Х + 3 = 4х - 5
3х = 8
Х = 8/3 = 2 2/3