(4^(4n-2))*(0.2^-2n)/(80^(2n-1)

Question

(4^(4n-2))*(0.2^-2n)/(80^(2n-1)

Answer 1

(4^(4n-2))*(0.2^-2n)/(80^(2n-1)=(16^2n/16*5^2n)/(80^2n/80)=80^2n/16*80/80^2n=5

Answer 2

(4^(4n-2))*(0.2^-2n)/(80^(2n-1))=(16^2n/16*5^2n)/(80^2n/80)=(80^2n)/16*80/(80^2n)=

=400n*80/(80^2*n)=32000n/(6400n)=5n/n=5