0\\OD3:x\ne\frac{3}2\\\\\\x^2+2x-3>0\\(x+3)(x-1)>0\\\\\boxed{x\in(-3;1)\cup(\frac{3}2;+\infty)}" alt="\frac{x^2+2x-3}{2x-3}>0\\OD3:x\ne\frac{3}2\\\\\\x^2+2x-3>0\\(x+3)(x-1)>0\\\\\boxed{x\in(-3;1)\cup(\frac{3}2;+\infty)}" align="absmiddle" class="latex-formula">